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Let’s say string s has period k if si=si+k for all i from 1 to |s|−k (|s| means length of string s) and k is the minimum positive integer with this property.

Some examples of a period: for s=“0101” the period is k=2, for s=“0000” the period is k=1, for s=“010” the period is k=2, for s=“0011” the period is k=4.

You are given string t consisting only of 0’s and 1’s and you need to find such string s that:

String s consists only of 0’s and 1’s;

The length of s doesn’t exceed 2⋅|t|; String t is a subsequence of string s; String s has smallest possible period among all strings that meet conditions 1—3. Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t=“011” is a subsequence of s=“10101”.

Input

The first line contains single integer T (1≤T≤100) — the number of test cases.

Next T lines contain test cases — one per line. Each line contains string t (1≤|t|≤100) consisting only of 0’s and 1’s.

Output

Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.

Example

inputCopy 4 00 01 111 110 outputCopy 00 01 11111 1010 Note In the first and second test cases, s=t since it’s already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.

In the third test case, there are shorter optimal solutions, but it’s okay since we don’t need to minimize the string s. String s has period equal to 1.

题意

给你一个二进制字符串t，求一个字符串s，满足t是s的子序列，s的长不超过t的两倍，且s的周期最小 思路 因为是二进制字符串，我们让它01或10交替（t的每一个字符变为两个），就可以保证T=2，且s的长度不超过2倍t的长度。 当然，如果字符串t中只有‘1’或者‘0’的话，T=1，我们直接让s=t即可

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